4. Ifline m has the equation y = 3x - 1, and line k is perpendicular to m and goes through the point (-4,3), find the equation of line k.

Respuesta :

Answer:

The equation of the line k is

[tex]y=-\frac{1}{3}x+\frac{5}{3}[/tex]

Explanation:

Given that k is perpendicular to line m, defined as:

y = 3x - 1

the slope of k is the negative reciprocal of the slope of line m.

The slope of m is 3

The negative reciprocal of m is -1/3 (this is the slope of k)

Therefore, k is in the form

[tex]y=-\frac{1}{3}x+b[/tex]

Since this line passes through the point (x, y) = (-4, 3), we can use this to obtain the value for the y-intercept, b

[tex]\begin{gathered} 3=-\frac{1}{3}(-4)+b \\ \\ 3=\frac{4}{3}+b \end{gathered}[/tex]

Solving for b by subtracting 4/3 from both sides

[tex]\begin{gathered} b=3-\frac{4}{3} \\ \\ =\frac{5}{3} \end{gathered}[/tex]

The equation is therefore,

[tex]y=-\frac{1}{3}x+\frac{5}{3}[/tex]