step 1
Find the slope of the line represented by the table of values
take the points
(-8,13) and (-4,5)
m=(5-13)/(-4+8)
m=-8/4
m=-2
step 2
Write the equation of the line that contains the point (-8,6) and has the same slope as the line represented by the table
y=mx+b
we have
m=-2 -----> the same slope of the given line
point (-8,6)
substitute in the equation of the line in slope intercepot form
6=-2*(-8)+b
solve for b
6=16+b
b=-10
therefore
teh equatiion of the line is
y=-2x-10
