Given:
Charge, Q = 45 C
Potential difference, V = 1.0 x 10⁸ V
Time, t = 0.030 s
Let's solve for the following:
• (A). What is the current of the lightning strike?
To find the current, apply the formula:
[tex]I=\frac{Q}{t}[/tex]Where:
I si the current
Q is the charge = 45 C
t is the time = 0.030 s
Thus, we have:
[tex]\begin{gathered} I=\frac{45}{0.030} \\ \\ I=1500\text{ A} \end{gathered}[/tex]Therefore, the current of the lightning strike is 1500 Amperes.
• (B). How much energy is released by the lightning bolt?
To find the amount of energy released, apply the formula:
[tex]E=V\times Q[/tex]where:
E is the Energy released
V is the potential difference, V = 1.0 x 10⁸ V
Q is the charge = 45 C
Thus, we have:
[tex]\begin{gathered} E=1.0\times10^8\ast45 \\ \\ E=4.5\times10^9\text{ J} \end{gathered}[/tex]Therefore, the energy released is 4.5 x 10⁹ Joules.
ANSWER:
(a). 1500 A
(b). 4.5 x 10⁹ J
