Given:
The coordinates of Quadrilateral ABCD is A(-2, 2), B(-2, 4), C(2, 4), and D(2, 2).
The quadrilateral is transformed with the rule,
[tex](x,y)\rightarrow\mleft(x+7,y-1\mright)[/tex]It becomes,
[tex]\begin{gathered} A\mleft(-2,2\mright)\rightarrow A^{\prime}\mleft(-2+7,2-1\mright)=A^{\prime}(5,1) \\ B\mleft(-2,4\mright)\rightarrow B^{\prime}(-2+7,4-1)=B^{\prime}(5,3) \\ C\mleft(2,4\mright)\rightarrow C^{\prime}(2+7,4-1)=C^{\prime}(9,3) \\ D(2,2)\rightarrow D^{\prime}(2+7,2-1)=D^{\prime}(9,1) \end{gathered}[/tex]Now, join the corresponding vertices of both the quadrilateral with the line segment.
After joining the vertices of the quadrilateral ABCD and A'B'C'D'. it gives the 3-dimensional shape- a rectangular prism.
