Given:
a.) The length of a rectangle is 2 inches more than its width.
Since the length of a rectangle is 2 inches more than its width, we can say that,
Width = W
Length = L = W + 2
Determine the width with respect to its Perimeter, we get:
[tex]\text{ Perimeter = P}[/tex][tex]\text{ P = 2W + 2L}[/tex][tex]\text{ P = 2W + 2(W + 2)}[/tex][tex]\text{ P = 2W + 2W + }4[/tex][tex]\text{ P = 4W + }4[/tex][tex]\text{ P - 4 = 4W}[/tex][tex]\text{ }\frac{\text{P - 4}}{4}\text{ = }\frac{\text{4W}}{4}[/tex][tex]\text{ }\frac{\text{P - 4}}{4}\text{ = W}[/tex]Therefore, the answer is D.
