We will have the following:
First, we can see that the probability of picking an even number at first is:
[tex]P_1=\frac{3}{6}\Rightarrow P_1=\frac{1}{2}[/tex]
And then, the probability of picking another even card without replacing the previous one will be:
[tex]P_2=\frac{2}{5}[/tex]
Now, the probability of this happening one after the other will be:
[tex]\begin{gathered} P_3=P_1P_2\Rightarrow P_3=\frac{1}{2}\ast\frac{2}{5} \\ \\ \Rightarrow P_3=0.2 \end{gathered}[/tex]
So, the probability will be of 20%.
