Hello!
First, let's write the coordinates of each vertex of this parallelogram:
• A (-4, 2)
,
• B (2, 2)
,
• C (5, -2)
,
• D (-1, -2)
As line AB is parallel to the x-axis, we can find its measurement without formulas. We just need to count the number of squares from one point to the other.
So,
AB = 6 units.
We will follow the same reasoning to calculate CD (because it's also parallel to the x-axis).
CD = 6 units.
Now we have to use the formula of the distance between two points to calculate the sides BC and DA. The formula is:
[tex]d_{A,B}=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}[/tex]
As we know the formula, let's replace it with the coordinates:
BC: 5 units
[tex]\begin{gathered} d_{B,C}=\sqrt{\left(x_C-x_B\right)^2+\left(y_C-y_B\right)^2} \\ d_{B,C}=\sqrt{(5-2)^2+(-2-2)^2} \\ d_{B,C}=\sqrt{3^2+(-4)^2} \\ d_{B,C}=\sqrt{9+16} \\ d_{B,C}=\sqrt{25} \\ d_{B,C}=5\text{ units} \end{gathered}[/tex]
DA: 5 units
We can solve it using the same formula as I used to solve BC, but now I'll show you how to solve it using Pythagoras Theorem (I think it will be easier). Look:
Solving by Pythagoras, we'll obtain:
[tex]\begin{gathered} x^2=4^2+3^2 \\ x^2=16+9 \\ x^2=25 \\ x=\sqrt{25} \\ x=5\text{ units} \end{gathered}[/tex]
Remembering: the perimeter is the sum of all the sides of a figure. So, we will have:
[tex]\begin{gathered} P=AB+BC+CD+DA \\ P=6+5+6+5 \\ P=22\text{ units} \end{gathered}[/tex]
