8.[–/1 Points]DETAILSALEXGEOM7 9.2.012.MY NOTESASK YOUR TEACHERSuppose that the base of the hexagonal pyramid below has an area of 40.6 cm2 and that the altitude of the pyramid measures 3.7 cm. A hexagonal pyramid has base vertices labeled M, N, P, Q, R, and S. Vertex V is centered above the base.Find the volume (in cubic centimeters) of the hexagonal pyramid. (Round your answer to two decimal places.) cm3

81 PointsDETAILSALEXGEOM7 92012MY NOTESASK YOUR TEACHERSuppose that the base of the hexagonal pyramid below has an area of 406 cm2 and that the altitude of the class=

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Solution

- The base is a regular hexagon. This implies that it can be divided into equal triangles.

- These equal triangles can be depicted below:

- If each triangle subtends an angle α at the center of the hexagon, it means that we can find the value of α since all the α angles are subtended at the center of the hexagon using the sum of angles at a point which is 360 degrees.

- That is,

[tex]\begin{gathered} α=\frac{360}{6} \\ \\ α=60\degree \end{gathered}[/tex]

- We also know that regular hexagon is made up of 6 equilateral triangles.

- Thus, the formula for finding the area of an equilateral triangle is:

[tex]\begin{gathered} A=\frac{\sqrt{3}}{4}x^2 \\ where, \\ x=\text{ the length of 1 side.} \end{gathered}[/tex]

- Thus, the area of the hexagon is:

[tex]A=6\times\frac{\sqrt{3}}{4}x^2[/tex]

- With the above formula we can find the length of the regular hexagon as follows:

[tex]\begin{gathered} 40.6=6\times\frac{\sqrt{3}}{4}x^2 \\ \\ \therefore x=15.626947286066 \end{gathered}[/tex]

- The formula for the volume of a hexagonal pyramid is:

[tex]\begin{gathered} V=\frac{\sqrt{3}}{2}b^2\times h \\ where, \\ b=\text{ the base} \\ h=\text{ the height.} \end{gathered}[/tex]

- Thus, the volume of the pyramid is

[tex]\begin{gathered} V=\frac{\sqrt{3}}{2}\times15.626947286066^2\times3.7 \\ \\ V=782.49cm^3 \end{gathered}[/tex]

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