Recall the area of a rectangle is determined by the formula
[tex]\begin{gathered} A_{\text{rectangle}}=lw \\ \text{where} \\ l\text{ and }w\text{ are the dimensions of the rectangle} \end{gathered}[/tex]Given the following
w = 4 3/4 ft
l = 6 4/5 ft
Convert the following given into improper fraction first
[tex]\begin{gathered} w=4\frac{3}{4}\text{ ft}\Longrightarrow w=\frac{19}{4}\text{ ft} \\ l=6\frac{4}{5}\text{ ft }\Longrightarrow l=\frac{34}{5}\text{ ft} \end{gathered}[/tex]Next, substitute those values to the given formula for solving the area of the rectangle
[tex]\begin{gathered} A=lw \\ A=\frac{34}{5}\text{ ft}\cdot\frac{19}{4}\text{ft} \\ A=\frac{646}{20}\text{ ft}^2 \\ \text{Convert the final answer back into mixed fractions} \\ A=\frac{646}{20}\text{ ft}^2\Longrightarrow A=32\frac{3}{10}\text{ ft}^2 \\ \\ \text{Therefore, the area of the rectangle is} \\ 32\frac{3}{10}\text{ ft}^2 \end{gathered}[/tex]