Given
Volume of the oxygen gas is
[tex]V=0.5L=0.0005m^3[/tex]The temperature is
[tex]T=3^oC[/tex]Pressure is
[tex]\begin{gathered} P=1.5atm \\ \Rightarrow P=1.5\times101325=151,987.5Pa \end{gathered}[/tex]To find
The translational kinetic energy
Explanation
The translational kinetic energy is given by
[tex]K=\frac{3}{2}nRT[/tex]For ideal gas,
[tex]PV=nRT[/tex]Thus,
[tex]\begin{gathered} K=\frac{3}{2}PV \\ \Rightarrow K=\frac{3}{2}\times151987.5\times0.0005 \\ \Rightarrow K=113.99J \end{gathered}[/tex]Conclusion
The translational kinetic energy is 113.99J
