EXPLANATION:
We are given a circle K with radius KG. Note here that line KJ and line KG are both radii of the circle given.
Also we know that a line tangent to a circle at the point of intersecting with the radius forms a 90-degree angle with the radius.
We can now extract the following triangle from the diagram provided;
We now have a right triangle which we shall solve by use of the Pythagorean theorem;
[tex]a^2+b^2=c^2[/tex]
Where we have c as the longest side (hypotenuse) and then a and b are the two other sides. Substituting into the equation above now gives us;
[tex]\begin{gathered} a^2+b^2=c^2 \\ KG^2+6^2=8^2 \\ KG^2+36=64 \end{gathered}[/tex]
Subtract 36 from both sides;
[tex]\begin{gathered} KG^2+36-36=64-36 \\ KG^2=28 \end{gathered}[/tex]
Take the square root of both sides;
[tex]\begin{gathered} \sqrt[]{KG^2}=\sqrt[]{28} \\ KG=5.2915 \end{gathered}[/tex]
Rounded to the nearest tenth, the answer is;
ANSWER:
[tex]KG=5.3[/tex]
