A construction worker pushes a wheelbarrow 5.0 m with a horizontal force of 250.0 N. How much work is done by the worker on the wheelbarrow

Respuesta :

Given data

*A construction worker pushes a wheelbarrow at a distance is d = 5.0 m

*The given horizontal force is F = 250.0 N

The formula for the work is done by the worker on the wheelbarrow is given as

[tex]W=F\times d[/tex]

Substitute the known values in the above expression as

[tex]\begin{gathered} W=(250.0)(5.0) \\ =1250\text{ J} \end{gathered}[/tex]

Hence, the work done by the worker on the wheelbarrow is W = 1250 J