determine whether or not each spaceship trip below has the same speed as Saiges spaceship

1) Since Saige's spaceship makes 588 km in 60 seconds we can find its velocity:
[tex]\begin{gathered} V=\frac{d}{t} \\ V=\frac{588}{60}=\frac{49}{5}\text{ =9.8 km /s} \\ \\ V_2=\frac{441}{45}=\frac{49}{5} \\ V_3=\frac{215}{25}=\frac{43}{5} \\ V_4=\frac{649}{110}=\frac{59}{10} \end{gathered}[/tex]2) After simplifying we can state:
441/45 = has the same speed as Saige's spaceship
215/25 = does not have the same speed as Saige's space
649/110 =does not have the same speed as Saige's space