So we want to find the equation of a line parallel to
[tex]y=-\frac{4}{5}x+12[/tex]Passing through the point (-6,2).
First, remember that a line is parallel to other if their slopes are the same.
Then, the slope of our parallel line will be also -4/5.
Remember that a line has the following equation:
[tex]y=mx+b[/tex]Where m is the slope and b is the y-intercept.
Now, we know that the parallel line has slope = -4/5 and passes through the point (x,y) = (-6,2), so we could replace in our previous equation as follows:
[tex]\begin{gathered} 2=-\frac{4}{5}(-6)+b \\ 2=\frac{24}{5}+b \\ b=2-\frac{24}{5} \\ b=-\frac{14}{5} \end{gathered}[/tex]Therefore, the equation of the parallel line to y=(-4/5)x+12 passing through (-6,2) is:
[tex]y=-\frac{4}{5}x-\frac{14}{5}[/tex]
