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A circular path 4 feet wide has an inner diameter of 650 feet. How much farther is it around the outer edge of the path than around the inner edge? Round to the nearest hundredth. Use 3.14 for pie

A circular path 4 feet wide has an inner diameter of 650 feet How much farther is it around the outer edge of the path than around the inner edge Round to the n class=

Respuesta :

step 1

Find out the circumference of the outer edge

Find out the radius

r=(650/2)+4

r=329 ft

so

[tex]\begin{gathered} C=2\pi\cdot r \\ C=2\cdot3.14\cdot329 \\ C=2,066.12\text{ ft} \end{gathered}[/tex]

step 2

Find out the circumference of the inner edge

r=650/2=325 ft

substitute

[tex]\begin{gathered} C=2\cdot3.14\cdot325 \\ C=2,041\text{ ft} \end{gathered}[/tex]

Find out the difference

2,066.12-2,041=25.12 ft

therefore

the answer is 25.12 ft

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