The general slope intercept form is : y = m * x + b
Where m is the slope and b is y - intercept
Given the equation of the line : x + 3y = 8
Write the equation in slope intercept form to find the slope of the line
so, solve for y :
[tex]\begin{gathered} x+3y=8 \\ 3y=-x+8 \\ \\ y=-\frac{1}{3}x+\frac{8}{3} \end{gathered}[/tex]So, the slope of the given line = -1/3
The parallel lines have the same slope
so, the slope of the required line = -1/3
And the equation will be :
[tex]y=-\frac{1}{3}x+b[/tex]Find the value of b using the given point ( 5 , -6 )
When x = 5 , y = -6
[tex]\begin{gathered} -6=-\frac{1}{3}\cdot5+b \\ -6=-\frac{5}{3}+b \\ -6+\frac{5}{3}=b \\ \\ b=-\frac{13}{3} \end{gathered}[/tex]So, the equation of the line will be :
[tex]y=-\frac{1}{3}x-\frac{13}{3}[/tex]it can be written as : 3y = -x - 13
[tex]x+3y=-13[/tex]