A committee must be formed with 4 teachers and 4 students. If there are 7 teachers to choose from, and 9 students, how many different ways could the committee be made?

Respuesta :

ANSWER

4,410

EXPLANATION

The number of ways we can choose 4 teachers from 7 teachers is,

[tex]_7C_4=\frac{7!}{(7-4)!\times4!}=\frac{7\times6\times5\times4!}{3!\times4!}=\frac{7\times6\times5}{3\times2}=\frac{7\times6\times5}{6}=7\times5=35[/tex]

There are 35 ways of choosing 4 teachers out of 7.

And the number of ways we can choose 4 students from 9 students is,

[tex]\begin{gathered} _9C_4=\frac{9!}{(9-4)!\times4!}=\frac{9\times8\times7\times6\times5\times4!}{5!\times4!}=\frac{9\times8\times7\times6\times5}{5\times4\times3\times2} \\ _9C_4=\frac{9\times8\times7}{4}=\frac{9\times(2\times4)\times7}{4}=9\times7\times2=126 \end{gathered}[/tex]

There are 126 ways of choosing 4 students out of 9.

The committee is formed by 4 teachers and 4 students. The number of ways it can be made is,

[tex]_7C_4\times_9C_4=35\times126=4,410[/tex]

Hence, there are 4,410 ways to choose 4 students and 4 teachers out of 9 students and 7 teachers.