A rectangle has a length of 9 inches and a widt of 5 inches whose sides are changing. The length is increasing by 3 in/sec and the width is shrinking at 9 in/sec. What is the rate of change of the perimeter?

Respuesta :

Given:

A rectangle has a length of 9 inches and a width of 5 inches whose sides are changing. The length is increasing by 3 in/sec and the width is shrinking at 9 in/sec.

To find:

The rate of change of the perimeter.

Solution:

It is known that the perimeter of the rectangle is twice the sum of length and width.

[tex]P=2(l+w)[/tex]

DIfferentiate the perimeter with respect to t:

[tex]\frac{dP}{dt}=2(\frac{dl}{dt}+\frac{dw}{dt})[/tex]

From the given information:

[tex]\begin{gathered} \frac{dP}{dt}=2(3-9) \\ =2(-6) \\ =-12 \end{gathered}[/tex]

Thus, the perimeter of the rectangle is decreasing at the rate of 12 inches per second.

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