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Question 6:A particle of mass 0.2 kg is moving in a straight line at speed 2.5ms, a constant force of magnitude FN is applied to it in the direction in which it is moving. The speed of the particle 5 seconds later is 4.5ms Find the value of F, magnitude of the force applied.

Respuesta :

First, let's calculate the particle acceleration, using the formula below:

[tex]\begin{gathered} V=V_0+a\cdot t \\ 4.5=2.5+a\cdot5 \\ 5a=4.5-2.5 \\ 5a=2 \\ a=\frac{2}{5}=0.4\text{ m/s}^2 \end{gathered}[/tex]

Now, to find the force applied, let's use the second law of Newton:

[tex]\begin{gathered} F=m\cdot a \\ F=0.2\cdot0.4 \\ F=0.08\text{ N} \end{gathered}[/tex]

Therefore the value of F is 0.08 N.

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