[tex]\Delta\text{H}_{\text{ rxn}}\text{ = 3}\Delta\text{H}_{\text{CO}_2}\text{ + 4}\Delta\text{H}_{\text{H}_2\text{O}}\text{ }-\text{ }\Delta\text{H}_{\text{ C}_3\text{H}_8}\text{ }-5\Delta\text{H}_{\text{O}_2}[/tex][tex]\Delta\text{H}_{\text{ rxn}}\text{ = 3\lparen-393.5 kJ/mol\rparen + 4\lparen-285.8 kJ/mol\rparen }-\text{ \lparen-103.8 kJ/mol\rparen }-5(0\text{ kJ/mol})[/tex][tex]\Delta\text{H}_{\text{ rxn}}\text{ = -2219.9 kJ/mol}[/tex]
The answer is -2219.9 kJ/mol
