Given the fucntion:
f(x) = tanx
Let's graph the function and input the correct values in the box.
• To find the y-intercept of the function, input 0 for x and solve:
[tex]\begin{gathered} f(0)=\tan 0 \\ \\ f(0)=0 \end{gathered}[/tex]
Therefore, the y-intercept is:
(0, 0)
• The period of the function:
The fundamental period of a tangent function is π.
Now, let's find points on the graph:
Therefore, the points are:
[tex]\mleft(-\frac{\pi}{3},-\sqrt{3}\mright),\mleft(-\frac{\pi}{4},-1\mright),\mleft(0,0\mright),\mleft(\frac{\pi}{4},1\mright),\mleft(\frac{\pi}{3},\sqrt{3}\mright)[/tex]
ANSWER:
The tangent function's period is π . The y-intercept of the function is (0, 0).
The points are:
[tex](-\frac{\pi}{3},-\sqrt[]{3}),(-\frac{\pi}{4},-1),(0,0),(\frac{\pi}{4},1),(\frac{\pi}{3},\sqrt[]{3})[/tex]
