Calculate the answers. 13. An orbiting satellite is positioned 3,105 mi above the earth (rearth = 3,959 mi) and orbits the earth once every 201.3 min. Assuming its orbit is a circle, find the distance traveled in 50.0 min.

Respuesta :

first you will calculate the speed of the orbiting satelite

[tex]\text{speed = }\frac{dis\tan ce}{time}[/tex]

distance = circumference of the of the orbit

[tex]\begin{gathered} \text{circumference = 2}\times\pi\times\text{ r} \\ r\text{ = radius of the earth + the height of the satelite above the earth} \\ r\text{ = 3105+3959 =7064mi} \end{gathered}[/tex][tex]\text{circ of the orbit = }2\text{ }\times3.142\times7064=\text{ 44390.176}[/tex][tex]\text{speed = }\frac{44390.176}{201.3}\text{ = 220.52mi/min}[/tex]

distance covered in 50.0 min

distance = speed X time

[tex]\text{distance = 220.52}\times50=11026mi[/tex]

the distance traveled is 11026 mi