Solution
Given that
Area f small square = 40 inches squared.
[tex]\begin{gathered} a=40 \\ \\ \text{ since a}=l^2 \\ \\ \Rightarrow40=l^2 \\ \\ \Rightarrow l=\sqrt{40} \end{gathered}[/tex]Let the side of the large square be L
Since the large square has sides that are 8 times longer than the small square
=> L = 8l
[tex]\begin{gathered} \Rightarrow L=8l \\ \\ \Rightarrow L=8(\sqrt{40}) \end{gathered}[/tex]Hence, the area of Large square is;
[tex]A=L^2=(8\sqrt{40})^2=64\times40=256[/tex]Hence, the area of the large square is: 256 inches squared.
