Answer:
Explanation:
• Car 1 leaves point A at 5:30 p.m., driving due south at an average speed of 35 mph.
,• Car 2 leaves point A at 6:30 p.m., driving due north at an average speed of 45 mph.
At 9:30 pm, the time taken by the cars is:
[tex]\begin{gathered} Car\;1:9:30-5:30=4\text{ hours} \\ Car\;2:9:30-6:30=3\text{ hours} \end{gathered}[/tex]The distance covered by each car is:
[tex]\begin{gathered} Distance=Speed\times Time \\ \text{Car 1's distance}=35\times4=140\text{ miles} \\ \text{Car 2's distance}=45\times3=135\text{ miles} \end{gathered}[/tex]Since car 1 drives due South and Car 2 due North of point A:
Therefore, the distance between the drivers at 9:30 p.m. will be:
[tex]Distance=140+135=275\text{ miles}[/tex]The two drivers are 275 miles apart at 9:30 pm.
