Respuesta :
1) Molar mass of Allicin.
1.1- Write the formula.
[tex]C_6H_{10}OS_2[/tex]1.2- Look for the molar mass of each element in the formula.
C: 12.011 g/mol
H: 1.008 g/mol
O: 15.999 g/mol
S: 32.06 g/mol
1.3- Count how many atoms are there in the formula.
C: 6
H: 10
O: 1
S: 2
1.4- Set the equation.
[tex]TheMolarMass=(6*C)+(10*H)+(1*O)+(2*S)[/tex]Plug in the known values.
[tex]TheMolarMass=(6*12.011\text{ }g/mol)+(10*1.008\text{ }g/mol)+(1*15.999\text{ }g/mol)+(2*32.06\text{ }g/mol)[/tex][tex]MM=72.066\text{ }g/mol+10.08\text{ }g/mol+15.999\text{ }g/mol+64.12\text{ }g/mol[/tex][tex]MM=162.265\text{ }g/mol[/tex]The molar mass (MM) of Allicin (C6H10OS2) is 162.265 g/mol.
2) Moles of Allicin in the sample.
Allicin sample: 4.20 mg
The molar mass of Allicin (C6H10OS2) is 162.265 g/mol.
2.1- Convert mg to g.
1g = 1000 mg
[tex]g=4.20\text{ }mg*\frac{1\text{ }g}{1000\text{ }mg}=0.00420\text{ }g[/tex]2.2- Convert grams to moles.
The molar mass of Allicin (C6H10OS2) is 162.265 g/mol.
Allicin sample: 0.00420 g
[tex]mol\text{ }C_6H_{10}OS_2=0.00420\text{ }g\text{ }C_6H_{10}OS_2*\frac{1\text{ }mol\text{ }C_6H_{10}OS_2}{162.265\text{ }g\text{ }C_6H_{10}OS_2}=0.00002588\text{ }mol\text{ }C_6H_{10}OS_2[/tex]There are 0.00002588 moles of Allicin (C6H10OS2) in 4.20 mg of substance.
The result can also be expressed as 2.588*10^(-5) mol.
3) Molecules of Allicin in the sample.
The Avogadro's number is 6.022*10^(23).
1 mol C6H10OS2 = 6.022*10^(23) molecules C6H10OS2
Allicin sample: 0.00002588 mol.
[tex]molecules\text{ }of\text{ }C_6H_{10}OS_2=0.00002588\text{ }mol\text{ }C_6H_{10}OS_2*\frac{6.022*10^{23}\text{ }molecules}{1\text{ }mol\text{ }C_6H_{10}OS_2}=1.558*10^{19}\text{ }molecules\text{ }of\text{ }C_6H_{10}OS_2[/tex]There are 1.558*10^(19) molecules in the sample.
4) C atoms in the sample of Allicin.
The ratio of carbon in one molecule of Allicin is 6 C atoms: 1 molecule of Allicin.
Allicin sample: 1.558*10^(19) molecules C6H10OS2.
[tex]C\text{ }atoms=1.588*10^{19}\text{ }molecules*\frac{6\text{ }C\text{ }atoms}{1\text{ }molecule\text{ }C_6H_{10}OS_2}=9.35*10^{19}\text{ }C\text{ }atoms.[/tex]There are 9.35*10^(19) C atoms in the sample.
