The net of a cone is shown below. What is the surface area of the cone rounded to the nearest tenth of a square inch? Use π = 3.14.A. 125.6 in²B. 1,256.6 in²C. 175.8 in²D. 251.3 in²

The net of a cone is shown below What is the surface area of the cone rounded to the nearest tenth of a square inch Use π 314A 1256 inB 12566 inC 1758 inD 2513 class=

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ANSWER

[tex](C)175.8in^2[/tex]

EXPLANATION

The surface area of a cone can be found using the formula:

[tex]A=\pi r^2+\pi rl[/tex]

where l = slant height

r = radius

The diameter of the cone is given, but we can find the radius since the radius is half the diameter:

[tex]\begin{gathered} r=\frac{D}{2} \\ r=\frac{8}{2} \\ r=4\text{ units} \end{gathered}[/tex]

From the figure, the slant height of the cone is 10 units.

Hence, its surface area is:

[tex]\begin{gathered} A=(\pi\cdot4^2)+(\pi\cdot4\cdot10) \\ A=50.24+125.6 \\ A\approx175.8in^2 \end{gathered}[/tex]

The answer is option C.