ANSWER
[tex]\begin{gathered} \sin O=\frac{34}{35} \\ \\ \cos N=\frac{34}{35} \\ \\ \text{ They are equal.} \end{gathered}[/tex]
EXPLANATION
We want to express the trigonometric ratios as fractions in the simplest terms.
The trigonometric ratios SOHCAHTOA for right triangles for sine and cosine are:
[tex]\begin{gathered} \sin\theta=\frac{opposite}{hypotenuse} \\ \\ \cos\theta=\frac{adjacent}{hypotenuse} \end{gathered}[/tex]
Therefore, for the given triangle, we have that:
[tex]\begin{gathered} \sin O=\frac{34}{35} \\ \\ \cos N=\frac{34}{35} \end{gathered}[/tex]
As we see from the equations above, the sine of O and the cosine of N are equal.
