Compute the following probabilities for the standard normal Z variable. a. P(Z<1.36)

Solution
a.
[tex]\begin{gathered} p(Z<1.36)=0.91309 \\ \\ p(Z<1.36)=0.9131 \end{gathered}[/tex]b.
[tex]\begin{gathered} p(Z>-1.10)=0.86433 \\ \\ p(Z>-1.10)=0.8643 \end{gathered}[/tex]c.
[tex]\begin{gathered} p(-3.02