I put it in quadratic form but i don’t know where to go from there. I got X = -1/20y^2 + 4y +12

ANSWER:
p = -5
STEP-BY-STEP EXPLANATION:
We have that the form of the equation of the parabola is the following:
[tex](y-k)^2=4p\cdot(x-h)[/tex]In this case we have the following equation, we convert it into its correct form, just like this:
[tex]\begin{gathered} \mleft(x-8\mright)=-\frac{1}{20}\cdot\mleft(y+2\mright)^2 \\ (y+2)^2=-20\cdot(x-8) \end{gathered}[/tex]We compare and calculate the value of p, just like this:
[tex]\begin{gathered} 4p=-20 \\ p=-\frac{20}{4} \\ p=-5 \end{gathered}[/tex]