To solve this problem, we will compute the slope of the line and then we will use it to find the equation of the line.
To determine the slope of a line that passes through points (x₁,y₁), and (x₂,y₂), we can use the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}.[/tex]Substituting
[tex]\begin{gathered} (x_2,y_2)=(-1,4), \\ (x_1,y_1)=(1,5), \end{gathered}[/tex]in the above formula, we get:
[tex]s=\frac{4-5}{-1-1}=\frac{-1}{-2}=\frac{1}{2}.[/tex]Now, with the above slope, we use the following formula for the equation of a line with slope m:
[tex]y-y_1=m(x-x_1).[/tex]Finally, we substitute one of the points:
[tex]y-5=\frac{1}{2}(x-1)[/tex]and take the equation to its slope-intercept form:
[tex]\begin{gathered} y-5=\frac{1}{2}(x-1), \\ y-5=\frac{1}{2}x-\frac{1}{2}, \\ y=\frac{1}{2}x+\frac{9}{2}. \end{gathered}[/tex]