Dante is arranging 11 cans of food in a row on a shelf. He has 7 cans of beans, 3 cans of peas, and 1 can of carrots. In how many distinct orders can the cans be arranged if two cans of the same food are considered identical (not distinct)?

Respuesta :

Given:

The number of cans of food =11

The number of cans of beans=7

the number of cans of peas=3

the number of cans of carrots=1

Condition : two cans of the same food are considered identical.

To arrange the n objects in order,

[tex]\begin{gathered} \text{Number of ways= }\frac{n!}{r_1!r_2!r_3!} \\ =\frac{11!}{7!3!1!} \\ =\frac{39916800}{30240} \\ =1320 \end{gathered}[/tex]

Answer: the number of ways are 1320.