10.7 grams
The formula for calculating the molarity of a solution is given as:
[tex]\begin{gathered} molarity=\frac{moles}{volume} \\ moles=molarity\times volume \end{gathered}[/tex]Given the following parameters
molarity of NaOH = 1.11M
volume of solution = 241.0mL = 0.241L
Find the moles of NaOH
[tex]\begin{gathered} moles\text{ of Na}OH=\frac{1.11mol}{L}\times0.241L \\ moles\text{ of Na}OH=0.2675moles \end{gathered}[/tex]Determine the mass of solute (NaOH)
[tex]\begin{gathered} Mass\text{ of NaOH}=mole\times molar\text{ mass} \\ Mass\text{ of NaOH}=0.2675\times40 \\ Mass\text{ of NaOH}=10.7grams \end{gathered}[/tex]Hence the grams of solute that would be used to prepare the solution is 10.7grams
