If Tanisha wants the top of the ladder to reach exactly 8 feet up the building, what is X, the distance between the building and the base of the ladder in feet?

If Tanisha wants the top of the ladder to reach exactly 8 feet up the building what is X the distance between the building and the base of the ladder in feet class=

Respuesta :

Solution:

Given:

The right triangle can be sketched as shown below;

To get the distance between the building and the base of the ladder, we use the Pythagoras theorem since it is a right triangle.

[tex]\begin{gathered} \text{hypotenuse}^2=\text{adjacent}^2+\text{opposite}^2 \\ \\ \text{where;} \\ \text{hypotenuse}=10 \\ \text{adjacent}=x \\ \text{opposite}=8 \end{gathered}[/tex]

Hence,

[tex]\begin{gathered} \text{hypotenuse}^2=\text{adjacent}^2+\text{opposite}^2 \\ 10^2=x^2+8^2 \\ 100=x^2+64 \\ 100-64=x^2 \\ 36=x^2 \\ x=\sqrt[]{36} \\ x=6 \end{gathered}[/tex]

Therefore, the distance between the building and the base of the ladder in feet is 6 feet.

Ver imagen KardenP402651
Ver imagen KardenP402651