How many grams of calcium chloride are needed to produce 15.0 g of potassium chloride?CaCl(aq) + K2CO3(aq)2 KCl(aq) + CaCO3(aq)

Answer
B. 11.2 grams
Explanation:
Molar mass of CaCl = 110.98 g/mol
Molar mass of KCl = 74.5513 g/mol
From the balanced chemical equation of the reaction given;
1 mole CaCl produced 2 moles KCl.
In grams;
(1 mol x 110.98 g/mol) CaCl produce (2 mol x 74.5513 g/mol) KCl, i.e
110.98 g CaCl produced 149.10236 g KCl,
Therefore, the grams of CaCl needed to produce 15.0 g KCl will be:
[tex]\text{Grams of CaCl n}eeded\text{ }=\frac{110.98\text{ g }\times15.0\text{ g}}{149.10236\text{ g}}=11.2\text{ grams}[/tex]Therefore, 11.2 grams of calcium chloride are needed to produce 15.0 g of potassium chloride.