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Jason is pulling a box across the roompulling with a force of 16 newtons and his arm is making a 68 anglet with the horizontal what is the horizontal component of the he is pulling with?

Jason is pulling a box across the roompulling with a force of 16 newtons and his arm is making a 68 anglet with the horizontal what is the horizontal component class=

Respuesta :

The horizontal component of a force is defined as follows

[tex]F_x=F\cdot\cos \theta[/tex]

Where F = 16 N, and theta = 68. Let's use these values to find the horizontal component of F.

[tex]F_x=16N\cdot\cos 68\approx6N[/tex]

Therefore, the horizontal component of the pulling force is 6 Newtons.

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