Solution
Note: The event here is Mutually Exclusive,, meaning the 2 events can happen at the same time
Total number = 4 + 3 + 3+3 = 13
[tex]\begin{gathered} P\mleft(A\mright)+P\mleft(B\mright)-P\mleft(AnB\mright) \\ \frac{7}{13}\text{ + }\frac{7}{13}-\frac{4}{13} \\ \frac{7+7-4}{13} \\ \frac{10}{13} \end{gathered}[/tex][tex]F\text{inal Answer = }\frac{10}{13}\text{ }[/tex]