Respuesta :
Given:
The voltage in the transmission line is: V = 240000 v
The stepped-down voltage is: Vs = 40000 v
The turns of the primary coil of the transformer are: Np = 940
To find:
The turns of the secondary coil of the transformer.
Explanation:
The voltage in a transmission line is used to step down by using the transformer. Thus, the primary voltage of the transformer will be the voltage in the transmission line.
Thus, Vp = V = 240000 v
The primary voltage Vp, the secondary voltage Vs, the primary turns on the coil Np and the secondary turns on the coil Ns are related as:
[tex]\frac{V_p}{V_s}=\frac{N_p}{N_s}[/tex]Rearranging the above equation, we get:
[tex]\begin{gathered} N_s=N_p\frac{V_s}{V_p} \\ \\ N_s=940\times\frac{40000\text{ v}}{240000\text{ v}} \\ \\ N_s=940\times\frac{4}{24} \\ \\ N_s=156.67 \\ \\ N_s\approx157 \end{gathered}[/tex]Final answer:
The number of turns on the secondary coil of the transformer are approximately 157.
