we know that
The area of a triangle applying the law of sines is equal to
[tex]A=\frac{1}{2}\cdot p\cdot q\cdot\sin (O)[/tex]substitute the given values
[tex]\begin{gathered} A=\frac{1}{2}\cdot3.4\cdot3.2\cdot\sin (99^o) \\ A=5.37\text{ cm\textasciicircum{}2} \end{gathered}[/tex]the answer is
