We can compute the mean by;
[tex]\operatorname{mean}=\frac{47+42+44+45+43+45+48+46}{8}=45[/tex]and the standard deviation by;
[tex]\frac{\sum ^{}_{}(x-\operatorname{mean})^2}{\sum ^{}_{}f}=\frac{28}{8}=3.5[/tex]So the mean of the data set is 45.
The standard deviation is 3.5