ANSWER
Tyler was right
EXPLANATION
To answer the question, we have to find the rate at which the temperature dropped between 4pm - 6pm and 6pm - 10pm
By 4pm, the temperature was 25°F and by 6pm, the temperature was 17°F.
The temperature difference is:
T = 17 - 25 = -8°F
There are 2 hours between 4 and 6 pm.
Now, we divide by the number of hours that elapsed:
[tex]\text{Rate = }\frac{-8}{2\text{ hours}}\text{ =}-4\degree F\text{ / hr}[/tex]
By 6 pm the temperature was 17°F and by 10pm, the temperature was 8°F.
The temperature difference is:
T = 8 - 17 = -9°F
There are 4 hours between 6 and 10 pm.
Now, divide by the number of hours that elapsed:
[tex]\text{Rate = }\frac{-9}{4}\text{ = }-2.25\degree F\text{ / hr}[/tex]
As we can see, the rate at which the temperature dropped between 4pm and 6 pm is more (since it became colder at a faster rate during that period)
Therefore, Tyler was right.
