consider the right triangle inside the circle with a center at point E(1,1). which equation can be used to show how he pythagorean theorem can lead to an equation for the circle?

The standard form of a circle is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]Where
(h, k) is the center
r is the radius
Since the center is (1, 1), we can write:
[tex](x-1)^2+(y-1)^2=r^2[/tex]EG (hypotenuse of the right triangle) is the radius of the circle. Thus, we can say >>>
[tex](x-1)^2+(y-1)^2=(LengthOfEG)^2[/tex]The correct answer is
B