We are given the system of equations
[tex]\begin{gathered} 5x-y=4 \\ x+4y=2 \end{gathered}[/tex]and we are given the ordered pair (4, 0)
We want to determine if the given pair is a solution of the equations
Solution
We only need to test the ordered pair (4, 0) on both equation
From the ordered pair we have
[tex]\begin{gathered} x=4 \\ y=0 \end{gathered}[/tex]We put the value of x and y in the first equation
[tex]\begin{gathered} 5x-y=4 \\ We\text{ now try it now} \\ 5x-y=5(4)-0=20-0=20\ne4 \end{gathered}[/tex]Thus, the ordered pair is not a solution of the first equation
Now, we put x and y in the second equation
[tex]\begin{gathered} x+4y=2 \\ we\text{ now put the values of the ordered pair} \\ x+4y=4+4(0)=4+0=4\ne2 \end{gathered}[/tex]Thus, the ordered pair is not a solution of the second equation
Hence, the ordered pair is not a solution
No, it is not a solution.