Explanation
[tex]\frac{x}{6}+3\ge-2[/tex]Step 1
subtract 3 in both sides.
[tex]\begin{gathered} \frac{x}{6}+3\ge-2 \\ \frac{x}{6}+3-3\ge-2-3 \\ \frac{x}{6}\ge-5 \end{gathered}[/tex]Step 2
Multiply both sides by 6
[tex]\begin{gathered} \frac{x}{6}\ge-5 \\ \frac{x}{6}\cdot6\ge-5\cdot6 \\ x\cdot\frac{6}{6}\ge-30 \\ x\cdot1\ge-30 \\ x\ge-30 \end{gathered}[/tex]so, the answer is
[tex]x\ge-30[/tex]I hope this helps you
