Given:
The mass of the man is m = 110 kg
The man slides down with acceleration,
[tex]a=9\text{ m/s}^2[/tex]The acceleration due to gravity is
[tex]g=\text{ 9.8 m/s}^2[/tex]Required: The frictional force acting on the man.
Explanation:
The equation of motion to calculate frictional force is given as
[tex]\begin{gathered} mg-f=ma \\ f=mg-ma \\ =m(g-a) \end{gathered}[/tex]On substituting the values, the frictional force will be
[tex]\begin{gathered} f=110(9.8-9) \\ =\text{ 88 N} \end{gathered}[/tex]Final Answer: The frictional force is 88 N
