I really don't know where to start on this problem and I would like it if some could help me please.

We can draw the following picture:
Since we have a right triangle with hypotenuse equal to 28ft, we can use the trigonometric function. That is, we can write the following relationships:
[tex]\begin{gathered} \sin 30=\frac{RG}{28} \\ \text{and } \\ \cos 60=\frac{RG}{28} \end{gathered}[/tex]both give the same result.
If we use the first one, we have
[tex]\begin{gathered} RG=28\cdot\sin 30 \\ \end{gathered}[/tex]since sin30=0.5, we have
[tex]\begin{gathered} RG=28\cdot(0.5) \\ RG=14 \end{gathered}[/tex]that is, RG = 14 ft, which corresponds to the first option