Explain how to find the period and the critical points (Zeros, Maximums, Minimums, Asymptotes) of y= -cos(3x)+1

Expalantion:
The function is goiven below as
[tex]y=-cos(3x)+1[/tex]The graph is given below as
Step 1:
To figure out the period of the cosine function, we will use the relation below
[tex]\begin{gathered} \frac{2\pi}{B} \\ where, \\ B=3 \end{gathered}[/tex]Hence,
The period will be
[tex]\frac{2\pi}{3}[/tex]The minimum points is given below as
[tex]\mathrm{Minimum}\left(\frac{2\pi }{3}n,\:0\right)[/tex]The maximum points is given below as
[tex]\mathrm{Maximum}\left(\frac{\pi }{3}+\frac{2\pi }{3}n,\:2\right)[/tex]It has NO ASYMPTOTES
The y-intercept is given below as
[tex]\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)[/tex]The zeros is given below as
[tex]\mathrm{X\:Intercepts}:\:\left(\frac{2\pi n}{3},\:0\right)[/tex]