Total possible students is 39
The formula for probability is given below as,
[tex]\text{Probability}=\frac{\operatorname{Re}quired\text{ outcome}}{\text{Possible outcome}}[/tex]Probability of "Dual-enrolled" is given below as,
[tex]P(\text{Dual enrolled)=}\frac{20}{39}[/tex]Probability of "Not Dual-enrolled" is given below as,
[tex]P(\text{Not Dual-enrolled)=}\frac{19}{39}[/tex]Probability that both students are dual enrolled if selected without replacement will be,
[tex]P(\text{Both are Dual-enrolled)=}\frac{20}{39}\times\frac{19}{38}=\frac{10}{39}[/tex]Probability that 1st is Dual-enrolled and the second is Not dual-enrolled if selected without replacement will be,
[tex]P(1st\text{ student is Dual-enrolled and 2nd is Not)}=\frac{20}{39}\times\frac{19}{38}=\frac{10}{39}[/tex]Hence, P(Both are Dual-enrolled) = 10/39
P(1st Dual-enrolled and 2nd Not dual-enrolled) = 10/39