Solution:
Given:
[tex]\begin{gathered} P=\text{ \$}36000 \\ r=4.5\text{ \%}=\frac{4.5}{100}=0.045 \\ t=number\text{ of years} \end{gathered}[/tex]The function that gives Jane's salary in dollars can be modeled using the compound interest formula;
[tex]\begin{gathered} A=P(1+r)^t \\ \\ where: \\ A\text{ is the amount at the end of every year} \end{gathered}[/tex][tex]\begin{gathered} A=36000(1+0.045)^t \\ A=36000(1.045)^t \end{gathered}[/tex]Therefore,
[tex]A=36000(1.045)^t[/tex]