Solution
Step 1
Draw the table of total possible outcomes when 2 dice are tossed
Step 2
From the table, find all entries that sum up to six from the toss of the 2 dice
From the marked area on the table, we can see all entries that sum up to 6 as required. There are 5 of them
Step 3
Write an expression for the probability of an event occurring
[tex]\text{Probability of an event occurring = }\frac{\text{number of required events}}{Total\text{number of events}}[/tex]Number of required events = 5
Total number of events = 36
Step 4
Substitute into the formula and get the final answer
[tex]Pr(\text{obtaining a sum of 6) =}\frac{5}{36}[/tex]Hence, the probability of obtaining a sum of 6 when two fair dice are tossed = 5/36
