Respuesta :

Answer:

15.46atm

Explanations:

According to the ideal gas equation;

[tex]PV=nRT[/tex]

where:

• P is the ,pressure ,of the gas

,

• V is the volume of the gas = 1.1L

,

• n is the number of moles = 0.7mol

,

• R is the ,Gas constant, = 0.08206Latm/molK

,

• T is the temperature = 23 + 273 = 296K

Substitute the given parameters into the formula

[tex]\begin{gathered} P=\frac{nRT}{V} \\ P=\frac{0.7\times0.08206\times296}{1.1} \\ P=\frac{17.0028}{1.1} \\ P=15.46atm \end{gathered}[/tex]

Hence the pressure of the gas that will be exerted is 15.46atm

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